A particle is moving along a straight line. It covers distance S with a velocity V. Then it covers a distance 2S with a velocity 3V in the same direction. Then magnitude of average velocity of the particle is

A particle moving along the straight line travels first 3m distance with speed 2 m/s, second 3m distance with speed 3 m/s and the third 3m distance with speed 6 m/s. The average speed of the particle is :-

A particle moving in a straight line covers half the distance with speed of 3 m/s. The another half of the distance is covered in two equal time intervals with speed of 4.5 m/s and 7.5 m/s, respectively. The average speed of the particle during this motion is

When is the average velocity magnitude equal to the average speed?Only when a particle is moving with uniform velocity in a straight line.Whenever a particle is travelling in a straight line and not a curve.Only when a particle travels in a straight line without reversing its motion.Only when a particle travels in a straight line without stopping.

As shown in the figure, a particle is moving with constant speed π m/s. Considering its motion from A to B, the magnitude of the average velocity is:

The position of a particle moving in a straight line is given by the function S (t) = t3 − 6t2,t ≥ 0. The graph of S against t is shown. The corresponding velocity–time graph is alsoshown. The function describing the velocity is V(t) = 3t2 − 12t.1 2 3 41 2 3 45 650–5–10–10–20010–30S(t) = t3 – 6t2 V(t) = 3t2 – 12tVSt ta Find the average velocity of the particle for the intervals:i [3.5, 4.5] ii [3.9, 4.1] iii [3.99, 4.01]b From part a, what is the instantaneous velocity when t = 4?c i For what values of t is the velocity positive?ii For what values of t is the velocity negative