In a class of 72 students, 32 students cleared only Maths exam and 16 cleared only Physics exam. If four students could not clear both the subjects' exams, then how many students cleared both the subjects' exams? Ops: A. 20 B. 18 C. 10 D. 15
Question
In a class of 72 students, 32 students cleared only Maths exam and 16 cleared only Physics exam. If four students could not clear both the subjects' exams, then how many students cleared both the subjects' exams? Ops: A. 20 B. 18 C. 10 D. 15
Solution
To solve this problem, we need to follow these steps:
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First, we need to find out the total number of students who cleared either Maths or Physics or both. This can be done by subtracting the number of students who could not clear both the subjects from the total number of students in the class. So, 72 (total students) - 4 (students who could not clear both) = 68 students.
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Next, we need to find out the number of students who cleared only one subject. This is given as 32 (only Maths) + 16 (only Physics) = 48 students.
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Finally, to find out the number of students who cleared both the subjects, we subtract the number of students who cleared only one subject from the total number of students who cleared either one or both subjects. So, 68 (either one or both) - 48 (only one) = 20 students.
So, the answer is A. 20 students cleared both the subjects' exams.
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