he angle of depression of a shipviewed at a particular instant from thetop of a 75 m vertical cliff is 30°. Theship is sailing away from the cliff atconstant speed and 1 minute later itsangle of depression from the top ofthe cliff is 20°. De
Question
he angle of depression of a shipviewed at a particular instant from thetop of a 75 m vertical cliff is 30°. Theship is sailing away from the cliff atconstant speed and 1 minute later itsangle of depression from the top ofthe cliff is 20°. De
Solution
It seems like your question got cut off. However, based on the information provided, I can start solving the problem.
Step 1: Understand the problem The problem involves two right triangles formed by the observer at the top of the cliff, the ship at two different times, and the points directly below the observer on the water level.
Step 2: Use the angle of depression to find the distance of the ship from the cliff at the first instant The angle of depression is the angle formed by the observer's line of sight and the horizontal line. In a right triangle, this is equal to the angle at the ship. So, we have a 30° angle at the ship. We can use the tangent of this angle (opposite side / adjacent side) to find the distance of the ship from the cliff (the adjacent side). We know the opposite side (height of the cliff) is 75 m.
So, tan(30°) = 75 / distance => distance = 75 / tan(30°)
Step 3: Use the angle of depression to find the distance of the ship from the cliff at the second instant Similarly, we can find the distance of the ship from the cliff 1 minute later using the 20° angle of depression.
tan(20°) = 75 / distance => distance = 75 / tan(20°)
Step 4: Find the distance the ship sailed in 1 minute The distance the ship sailed in 1 minute is the difference between the distances calculated in steps 2 and 3.
Please provide the complete question so I can finish the solution.
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