The ionic radius of an ion is determined by its electronic arrangement and the number of electron shells it has.

1. K+ is larger than Na+ because potassium (K) is located below sodium (Na) on the periodic table, which means it has more electron shells. Even though both ions have lost one electron and have the same electronic arrangement (2.8.8), the extra shell in K+ increases its size.

2. Mg2+ is smaller than Na+ because magnesium (Mg) has lost two electrons compared to sodium's one, resulting in a smaller electronic arrangement (2.8 vs 2.8.8). When an atom loses electrons and forms a positive ion, the ion's size decreases because the electrons in the outer shell are removed and the remaining electrons are drawn closer to the nucleus due to its positive charge. Therefore, Mg2+ is smaller than Na+.

Question

The ionic radius of an ion is determined by its electronic arrangement and the number of electron shells it has.

1. K+ is larger than Na+ because potassium (K) is located below sodium (Na) on the periodic table, which means it has more electron shells. Even though both ions have lost one electron and have the same electronic arrangement (2.8.8), the extra shell in K+ increases its size.

2. Mg2+ is smaller than Na+ because magnesium (Mg) has lost two electrons compared to sodium's one, resulting in a smaller electronic arrangement (2.8 vs 2.8.8). When an atom loses electrons and forms a positive ion, the ion's size decreases because the electrons in the outer shell are removed and the remaining electrons are drawn closer to the nucleus due to its positive charge. Therefore, Mg2+ is smaller than Na+.

Knowee AI · Accepted Answer

The ionic radius of an ion is determined by its electronic arrangement and the number of electron shells it has.

1. K+ is larger than Na+ because potassium (K) is located below sodium (Na) on the periodic table, which means it has more electron shells. Even though both ions have lost one electron and have the same electronic arrangement (2.8.8), the extra shell in K+ increases its size.

2. Mg2+ is smaller than Na+ because magnesium (Mg) has lost two electrons compared to sodium's one, resulting in a smaller electronic arrangement (2.8 vs 2.8.8). When an atom loses electrons and forms a positive ion, the ion's size decreases because the electrons in the outer shell are removed and the remaining electrons are drawn closer to the nucleus due to its positive charge. Therefore, Mg2+ is smaller than Na+.

Study the information in the table and answer the questions that followIon ElectronicarrangementIonicradiusNa + 2.8 0.095K+ 2.8.8 0.133Mg2+ 2.8 0.065Explain why the ionicradius of (1 mark)K + is greater than that ofNa + Mg 2+ is smaller than that ofNa +

Question

Solution 1

Solution 2

Similar Questions

Upgrade your grade with Knowee