Suppose a hash table of size 10 uses linear probing for collision resolution and key%10 as hash function. If the key values that are hashed are as follows: {23, 55, 42, 3, 12} , what is the location of 12?
Question
Suppose a hash table of size 10 uses linear probing for collision resolution and key%10 as hash function. If the key values that are hashed are as follows: {23, 55, 42, 3, 12} , what is the location of 12?
Solution 1
To find the location of the key 12 in the hash table, we need to use the provided hash function, which is key%10.
Step 1: Apply the hash function to the key 12. 12 % 10 = 2
So, the location of the key 12 in the hash table is 2.
Solution 2
To find the location of 12 in the hash table, we need to use the provided hash function, which is key%10.
Step 1: Apply the hash function to the key The hash function is key%10. So, we calculate 12%10 which equals 2.
Step 2: Check the hash table at the calculated index We then check the hash table at index 2. If there is no collision (i.e., no other key has been hashed to this index), then 12 will be placed at this index.
Step 3: Resolve any collisions If there is a collision, we use linear probing to find the next available slot. This means we move linearly through the hash table, checking each slot until we find an empty one.
However, in this case, there is no collision at index 2, so 12 will be placed at index 2.
So, the location of 12 in the hash table is at index 2.
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