For which of the following quadratic equations are the roots 2 and 5?x2 + 7x - 10 = 0x2 - 11x - 10 = 0x2 - 7x + 10 = 0x2 - 3x - 10 = 0

The roots of a quadratic equation are given by the formula:

x = [-b ± sqrt(b² - 4ac)] / 2a

Where:

• a, b, and c are the coefficients of the quadratic equation ax² + bx + c = 0
• sqrt denotes the square root

The roots of the equation are 2 and 5, so we can set up two equations:

2 = [-b + sqrt(b² - 4ac)] / 2a 5 = [-b - sqrt(b² - 4ac)] / 2a

We can solve these equations for a, b, and c. However, there's a simpler way. In a quadratic equation, the sum of the roots is given by -b/a and the product of the roots is given by c/a.

So, for our roots 2 and 5:

Sum of roots = 2 + 5 = 7 = -b/a Product of roots = 2 * 5 = 10 = c/a

We can see that the equation that satisfies these conditions is:

x² - 7x + 10 = 0

So, the quadratic equation for which the roots are 2 and 5 is x² - 7x + 10 = 0.