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Select the correct answerWhat will be the output of the following Java code?class multidimention_array {  public static void main(String args[])  {    int arr[][] = new int[3][];    arr[0] = new int[1];    arr[1] = new int[2];    arr[2] = new int[3];         int sum = 0; for (int ct1 = 0; ct1 < 3; ++ct1)    for (int ct2 = 0; ct2 < ct1 + 1; ++ct2)        arr[ct1][ct2] = ct2 + 1; for (int ct1 = 0; ct1 < 3; ++ct1)    for (int ct2 = 0; ct2 < ct1 + 1; ++ct2)        sum += arr[ct1][ct2]; System.out.print(sum);   } }Options13101114

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Select the correct answerWhat will be the output of the following Java code?class multidimention_array {  public static void main(String args[])  {    int arr[][] = new int[3][];    arr[0] = new int[1];    arr[1] = new int[2];    arr[2] = new int[3];         int sum = 0; for (int ct1 = 0; ct1 < 3; ++ct1)    for (int ct2 = 0; ct2 < ct1 + 1; ++ct2)        arr[ct1][ct2] = ct2 + 1; for (int ct1 = 0; ct1 < 3; ++ct1)    for (int ct2 = 0; ct2 < ct1 + 1; ++ct2)        sum += arr[ct1][ct2]; System.out.print(sum);   } }Options13101114

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Solution

The output of the given Java code will be 10.

Here's the step by step explanation:

  1. A 2D array arr[][] is created with 3 rows and each row has a different number of columns. The first row has 1 column, the second row has 2 columns, and the third row has 3 columns.

  2. The first nested for loop assigns values to the elements of the array. For each row, it assigns values from 1 to the number of columns in that row.

  3. The second nested for loop calculates the sum of all elements in the array.

  4. The sum of all elements in the array is 1 (from the first row) + 1 + 2 (from the second row) + 1 + 2 + 3 (from the third row) = 10.

  5. The sum is printed out, so the output of the code is 10.

This problem has been solved

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