A drill, at its highest speed, rotates at 5500 rpm. If the drill takes 1.37 s to go from rest to full speed, how many revolutions does it make in that time? 62.9 rev 789 rev 395 rev 3.77×103 rev

To solve this problem, we need to use the formula for the distance travelled under constant acceleration, which is d = 0.5at^2. However, we first need to find the acceleration.

1. Convert the speed from rpm to revolutions per second (rps) because the time is given in seconds. 5500 rpm = 5500/60 rps = 91.67 rps.

2. The drill takes 1.37 seconds to reach this speed, so we can find the acceleration (a) using the formula a = Δv/Δt. a = 91.67 rps / 1.37 s = 66.91 rps^2.

3. Now we can find the distance (d) or in this case, the number of revolutions, using the formula d = 0.5at^2. d = 0.5 * 66.91 rps^2 * (1.37 s)^2 = 62.9 revolutions.

So, the drill makes 62

To solve this problem, we need to use the formula for the distance travelled under constant acceleration, which is d = 0.5at^2. However, we first need to find the acceleration.

1. Convert the speed from rpm to rps (revolutions per second) by dividing by 60. This gives us 5500/60 = 91.67 rps.

2. The acceleration is the change in speed divided by the time taken. In this case, it's 91.67 rps / 1.37 s = 66.91 rps^2.

3. Now we can find the number of revolutions. Using the formula d = 0.5at^2, we get d = 0.5*66.91 rps^2 * (1.37 s)^2 = 62.9 revolutions.

So, the drill makes 62.9 revolutions as it accelerates from rest to full speed.