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How do you initialize a pointer to the address of a variable 'x' ?Marks : 1Negative Marks : 0Answer hereint *ptr = x;int *ptr = &x;*int ptr;int *ptr = *x;

Question

How do you initialize a pointer to the address of a variable 'x' ?Marks : 1Negative Marks : 0Answer hereint *ptr = x;int *ptr = &x;*int ptr;int *ptr = *x;

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Solution

To initialize a pointer to the address of a variable 'x', you would use the following code:

int *ptr = &x;

Here's the step by step explanation:

  1. int *ptr; This line declares a pointer to an integer. The asterisk (*) is used to denote that 'ptr' is a pointer.

  2. = &x; This line assigns the address of 'x' to the pointer 'ptr'. The ampersand (&) is used to get the address of a variable.

So, int *ptr = &x; declares a pointer and initializes it to the address of 'x'.

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Similar Questions

In C, what is the result of declaring a pointer as int *ptr; without initialization?Marks : 1Negative Marks : 0Answer hereThe value of the variableptr points to a specific known memory locationptr contains a garbage value as its addressptr points to the memory location 0

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What is the correct syntax for declaring a pointer variable?Marks : 1Negative Marks : 0Answer hereint *ptr;pointer int *ptr;*int ptr;None of the mentioned options

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