To calculate the mass of zinc oxalate added to the flask, we need to use the given concentration of the solution. The concentration is given in g/L, but we want the mass in milligrams (mg), and the volume is given in mL.

Here are the steps to solve this problem:

1. Convert the concentration from g/L to mg/L. Since 1 g = 1000 mg, the concentration is 0.00165 g/L * 1000 = 1.65 mg/L.

2. Convert the volume from mL to L. Since 1 L = 1000 mL, the volume is 875.0 mL / 1000 = 0.875 L.

3. Multiply the concentration by the volume to get the mass of zinc oxalate. So, 1.65 mg/L * 0.875 L = 1.44 mg.

Therefore, the chemist has added approximately 1.44 mg of zinc oxalate to the flask. This answer has three significant digits, which is appropriate given the number of significant digits in the original problem.

Question

To calculate the mass of zinc oxalate added to the flask, we need to use the given concentration of the solution. The concentration is given in g/L, but we want the mass in milligrams (mg), and the volume is given in mL.

Here are the steps to solve this problem:

1. Convert the concentration from g/L to mg/L. Since 1 g = 1000 mg, the concentration is 0.00165 g/L * 1000 = 1.65 mg/L.

2. Convert the volume from mL to L. Since 1 L = 1000 mL, the volume is 875.0 mL / 1000 = 0.875 L.

3. Multiply the concentration by the volume to get the mass of zinc oxalate. So, 1.65 mg/L * 0.875 L = 1.44 mg.

Therefore, the chemist has added approximately 1.44 mg of zinc oxalate to the flask. This answer has three significant digits, which is appropriate given the number of significant digits in the original problem.

Knowee AI · Accepted Answer

To calculate the mass of zinc oxalate added to the flask, we need to use the given concentration of the solution. The concentration is given in g/L, but we want the mass in milligrams (mg), and the volume is given in mL.

Here are the steps to solve this problem:

1. Convert the concentration from g/L to mg/L. Since 1 g = 1000 mg, the concentration is 0.00165 g/L * 1000 = 1.65 mg/L.

2. Convert the volume from mL to L. Since 1 L = 1000 mL, the volume is 875.0 mL / 1000 = 0.875 L.

3. Multiply the concentration by the volume to get the mass of zinc oxalate. So, 1.65 mg/L * 0.875 L = 1.44 mg.

Therefore, the chemist has added approximately 1.44 mg of zinc oxalate to the flask. This answer has three significant digits, which is appropriate given the number of significant digits in the original problem.

A chemist adds 875.0mL of a /0.00165gL zinc oxalate ZnC2O4 solution to a flask.Calculate the mass in milligrams of zinc oxalate the chemist has added to the flask. Be sure your answer has the correct number of significant digits.

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