Given an array of integers called nums, you can perform the following operation while nums contains at least 2 elements:Choose the first two elements of nums and delete them.The score of the operation is the sum of the deleted elements.Your task is to find the maximum number of operations that can be performed, such that all operations have the same score.Return the maximum number of operations possible that satisfy the condition mentioned above.
Question
Given an array of integers called nums, you can perform the following operation while nums contains at least 2 elements:Choose the first two elements of nums and delete them.The score of the operation is the sum of the deleted elements.Your task is to find the maximum number of operations that can be performed, such that all operations have the same score.Return the maximum number of operations possible that satisfy the condition mentioned above.
Solution
The problem can be solved using a priority queue and a hash map. Here are the steps:
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First, sort the array in descending order. This is because we want to perform the operation with the largest numbers first to maximize the score.
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Initialize a priority queue and a hash map. The priority queue will store the scores of the operations, and the hash map will store the frequency of each score.
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Iterate through the array. For each pair of numbers, calculate their sum (which is the score of the operation), remove them from the array, and add the score to the priority queue and the hash map.
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While the priority queue is not empty, take the top element (which is the largest score), and check its frequency in the hash map. If the frequency is greater than 1, then we can perform another operation with the same score. So, decrement the frequency in the hash map, and add the score to the result.
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Finally, return the result, which is the maximum number of operations that can be performed with the same score.
This algorithm works because it always tries to perform the operation with the largest score first, and it ensures that all operations have the same score by checking the frequency of each score in the hash map. The time complexity is O(n log n) due to the sorting and the priority queue operations, and the space complexity is O(n) for the priority queue and the hash map.
Similar Questions
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You are given a 0-indexed integer array nums and an integer k. You have a starting score of 0.In one operation:choose an index i such that 0 <= i < nums.length,increase your score by nums[i], andreplace nums[i] with ceil(nums[i] / 3).Return the maximum possible score you can attain after applying exactly k operations.
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You are given an array A of size NLet M be the minimum value present in the array initiallyIn one operation, you can choose an element Ai ( 1 ≤ i ≤ N ) and an integer X ( 1 ≤ X ≤ 100 ), and set Ai = X.Determine the minimum number of operations required to make M the maximum value in the array A.
class Solution { public: int minOperations(vector<int>& nums, int k) { } }; complete the function using folloiwing statement User 100231. Minimum Operations to Exceed Threshold Value I User Accepted:1 User Tried:3 Total Accepted:1 Total Submissions:3 Difficulty:Easy You are given a 0-indexed integer array nums, and an integer k. In one operation, you can remove one occurrence of the smallest element of nums. Return the minimum number of operations needed so that all elements of the array are greater than or equal to k. Example 1: Input: nums = [2,11,10,1,3], k = 10 Output: 3 Explanation: After one operation, nums becomes equal to [2, 11, 10, 3]. After two operations, nums becomes equal to [11, 10, 3]. After three operations, nums becomes equal to [11, 10]. At this stage, all the elements of nums are greater than or equal to 10 so we can stop. It can be shown that 3 is the minimum number of operations needed so that all elements of the array are greater than or equal to 10. Example 2: Input: nums = [1,1,2,4,9], k = 1 Output: 0 Explanation: All elements of the array are greater than or equal to 1 so we do not need to apply any operations on nums. Example 3: Input: nums = [1,1,2,4,9], k = 9 Output: 4 Explanation: only a single element of nums is greater than or equal to 9 so we need to apply the operations 4 times on nums. Constraints: 1 <= nums.length <= 50 1 <= nums[i] <= 109 1 <= k <= 109 The input is generated such that there is at least one index i such that nums[i] >= k.
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