A student in the laboratory weighs out 2.57 g of glucose (C6H12O6). This amount contains Blank 1 Question 5 moles of glucose and Blank 2 Question 5 glucose molecules.
Question
A student in the laboratory weighs out 2.57 g of glucose (C6H12O6). This amount contains Blank 1 Question 5 moles of glucose and Blank 2 Question 5 glucose molecules.
Solution
To answer this question, we first need to calculate the number of moles of glucose. The molar mass of glucose (C6H12O6) is approximately 180.16 g/mol.
Step 1: Calculate the number of moles Number of moles = mass / molar mass Number of moles = 2.57 g / 180.16 g/mol = 0.0143 moles
So, Blank 1 = 0.0143 moles
Step 2: Calculate the number of molecules We know that 1 mole of any substance contains Avogadro's number (6.022 x 10^23) of molecules.
Number of molecules = number of moles x Avogadro's number Number of molecules = 0.0143 moles x 6.022 x 10^23 molecules/mole = 8.61 x 10^21 molecules
So, Blank 2 = 8.61 x 10^21 molecules
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