Look at the equations for the two reactions:Reaction 1 CuCO3(s) + 2HCl(aq) → CuCl2(aq) + H2O(l) + CO2(g)Reaction 2 CuO(s) + 2HCl(aq) → CuCl2(aq) + H2O(l)Reactive formula masses: CuO = 79.5; HCl = 36.5; CuCl2 = 134.5; H2O = 18The percentage atom economy for a reaction is calculated using:Calculate the percentage atom economy for Reaction 2.
Question
Look at the equations for the two reactions:Reaction 1 CuCO3(s) + 2HCl(aq) → CuCl2(aq) + H2O(l) + CO2(g)Reaction 2 CuO(s) + 2HCl(aq) → CuCl2(aq) + H2O(l)Reactive formula masses: CuO = 79.5; HCl = 36.5; CuCl2 = 134.5; H2O = 18The percentage atom economy for a reaction is calculated using:Calculate the percentage atom economy for Reaction 2.
Solution
To calculate the percentage atom economy for Reaction 2, we first need to understand the formula for atom economy:
Atom Economy (%) = (Mass of desired product / Total mass of reactants) * 100%
In Reaction 2, the desired product is CuCl2 and the reactants are CuO and HCl.
Step 1: Calculate the mass of the desired product (CuCl2) The reactive formula mass of CuCl2 is given as 134.5.
Step 2: Calculate the total mass of reactants (CuO + 2HCl) The reactive formula mass of CuO is given as 79.5. The reactive formula mass of HCl is given as 36.5, but since there are 2 moles of HCl in the reaction, we multiply this by 2 to get 73.
Adding these together, the total mass of reactants is 79.5 (CuO) + 73 (2HCl) = 152.5
Step 3: Substitute these values into the atom economy formula: Atom Economy (%) = (134.5 / 152.5) * 100% = 88.2%
So, the percentage atom economy for Reaction 2 is 88.2%.
Similar Questions
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