The work done by a force on an object is given by the equation W = F * d * cos(θ), where F is the force, d is the distance the object moves, and θ is the angle between the force and the direction of motion.

In this case, the force is the tension in the rope, which is 20.0 N. The distance the weight moves in half a revolution of a circle with radius 1.00 m is half the circumference of the circle, which is 0.5 * 2π * 1.00 m = π m.

However, the force from the rope is always perpendicular to the direction of motion of the weight. This means that θ = 90 degrees, and cos(90 degrees) = 0.

Therefore, the work done by the rope on the weight in half a revolution is W = 20.0 N * π m * 0 = 0 J.

So, the correct answer is a. 0.

Question

The work done by a force on an object is given by the equation W = F * d * cos(θ), where F is the force, d is the distance the object moves, and θ is the angle between the force and the direction of motion.

In this case, the force is the tension in the rope, which is 20.0 N. The distance the weight moves in half a revolution of a circle with radius 1.00 m is half the circumference of the circle, which is 0.5 * 2π * 1.00 m = π m.

However, the force from the rope is always perpendicular to the direction of motion of the weight. This means that θ = 90 degrees, and cos(90 degrees) = 0.

Therefore, the work done by the rope on the weight in half a revolution is W = 20.0 N * π m * 0 = 0 J.

So, the correct answer is a. 0.

Knowee AI · Accepted Answer

The work done by a force on an object is given by the equation W = F * d * cos(θ), where F is the force, d is the distance the object moves, and θ is the angle between the force and the direction of motion.

In this case, the force is the tension in the rope, which is 20.0 N. The distance the weight moves in half a revolution of a circle with radius 1.00 m is half the circumference of the circle, which is 0.5 * 2π * 1.00 m = π m.

However, the force from the rope is always perpendicular to the direction of motion of the weight. This means that θ = 90 degrees, and cos(90 degrees) = 0.

Therefore, the work done by the rope on the weight in half a revolution is W = 20.0 N * π m * 0 = 0 J.

So, the correct answer is a. 0.

I use a rope 1.00-m-long to swing a 1.00-kg weight around my head. The tension in the rope is 20.0 N. In half a revolution how much work is done by the rope on the weight?Select one:a.0b.20.0 Jc.31.4 Jd.123 J

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