If the effective voltage of an ac receptacle is 120V, what is the peak-to-peak voltage?Select one:a.169.7 Vb.240 Vc.339.4 Vd.84.8 V

The peak voltage of an AC circuit is given by the formula Vpeak = Vrms * sqrt(2), where Vrms is the effective voltage.

Step 1: Substitute the given Vrms value into the formula. In this case, Vrms = 120V.

Vpeak = 120V * sqrt(2)

Step 2: Calculate the value.

Vpeak = 169.7V

The peak-to-peak voltage is then 2 * Vpeak because it measures the total voltage swing of the AC signal.

Step 3: Substitute the calculated Vpeak into the formula.

Vpeak-to-peak = 2 * 169.7V

Step 4: Calculate the value.

Vpeak-to-peak = 339.4V

So, the peak-to-peak voltage of an AC receptacle with an effective voltage of 120V is 339.4V. Therefore, the correct answer is c. 339.4V.

The peak voltage of an AC circuit is given by the formula Vpeak = Vrms * sqrt(2), where Vrms is the effective voltage.

Step 1: Substitute the given Vrms value into the formula. In this case, Vrms = 120V.

Vpeak = 120V * sqrt(2)

Step 2: Calculate the value.

Vpeak = 169.7V

The peak-to-peak voltage is then 2 * Vpeak because it measures the total voltage swing from the positive to the negative peak.

Step 3: Substitute the calculated Vpeak into the formula.

Vpeak-to-peak = 2 * 169.7V

Step 4: Calculate the value.

Vpeak-to-peak = 339.4V

So, the peak-to-peak voltage of an AC receptacle with an effective voltage of 120V is 339.4V. Therefore, the correct answer is c. 339.4V.