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On the coordinate plane, the segment from J(0,–7) to K(–15,–7) forms one side of a rectangle. The rectangle has a perimeter of 54 units. Select all of the points that could be a vertex of the rectangle.(–15,12)(0,–1)(0,–19)(–15,5)Submit

Question

On the coordinate plane, the segment from J(0,–7) to K(–15,–7) forms one side of a rectangle. The rectangle has a perimeter of 54 units. Select all of the points that could be a vertex of the rectangle.(–15,12)(0,–1)(0,–19)(–15,5)Submit

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Solution

First, let's find the length of the segment JK. Since J and K have the same y-coordinate, the length of JK is simply the difference in their x-coordinates, which is |0 - (-15)| = 15 units.

The perimeter of a rectangle is given by the formula 2(length + width). We know the length of the rectangle is 15 units and the perimeter is 54 units. So, we can set up the equation 2(15 + width) = 54 to solve for the width. Simplifying, we get 30 + 2width = 54, so 2width = 24, and the width = 12 units.

Now, we know that the rectangle extends 12 units above and below the segment JK. So, the y-coordinates of the other two vertices of the rectangle must be -7 - 12 = -19 and -7 + 12 = 5.

Therefore, the points that could be a vertex of the rectangle are (0, -19) and (-15, 5).

This problem has been solved

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