A tank contains 40 liters of petrol. From it, 4 liters are drawn and replaced by kerosene. This process is further repeated two times. Calculate the amount of petrol left finally.19.8729.1623.1225
Question
A tank contains 40 liters of petrol. From it, 4 liters are drawn and replaced by kerosene. This process is further repeated two times. Calculate the amount of petrol left finally.19.8729.1623.1225
Solution
The problem involves a process of dilution where a certain amount of petrol is being replaced by kerosene multiple times. Here's how you can solve it:
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Initially, the tank is full with petrol, so it contains 40 liters of petrol.
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In the first operation, 4 liters of petrol are removed. This leaves 40 - 4 = 36 liters of petrol. The tank is then filled up with kerosene, so the total volume remains 40 liters.
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Now, the ratio of petrol to the total volume is 36/40. When 4 liters are removed, this ratio is applied to the removed volume, so 4 * (36/40) = 3.6 liters of petrol are removed. This leaves 36 - 3.6 = 32.4 liters of petrol in the tank.
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The process is repeated once more. The ratio of petrol to the total volume is now 32.4/40. When 4 liters are removed, 4 * (32.4/40) = 3.24 liters of petrol are removed. This leaves 32.4 - 3.24 = 29.16 liters of petrol in the tank.
So, the final amount of petrol left in the tank is 29.16 liters.
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