A string of mass 2000g and length 100metres is under tension of 150N. (i) Determine the linear density of the string (iii) Velocity of wave in the stringa.0.02N/M (ii) 0.866m/sb.0.02N/M (ii) 8.00m/sc.0.4N/M (ii) 8.00m/sd.0.4N/M (ii) 0.0866m/se.0.2N/M (ii) 0.866m/sf.0.03N/M (ii) 8.86m/s
Question
A string of mass 2000g and length 100metres is under tension of 150N. (i) Determine the linear density of the string (iii) Velocity of wave in the stringa.0.02N/M (ii) 0.866m/sb.0.02N/M (ii) 8.00m/sc.0.4N/M (ii) 8.00m/sd.0.4N/M (ii) 0.0866m/se.0.2N/M (ii) 0.866m/sf.0.03N/M (ii) 8.86m/s
Solution
The question seems to be asking for two things:
(i) The linear density of the string (ii) The velocity of a wave in the string
Let's solve this step by step:
(i) The linear density (μ) of a string is defined as the mass per unit length. It can be calculated using the formula:
μ = mass/length
Given that the mass of the string is 2000g (or 2kg, since 1kg = 1000g) and the length is 100m, we can substitute these values into the formula:
μ = 2kg / 100m = 0.02kg/m
So, the linear density of the string is 0.02kg/m.
(ii) The velocity (v) of a wave in a string under tension can be calculated using the formula:
v = sqrt(T/μ)
where T is the tension in the string and μ is the linear density. Given that the tension is 150N and we've just calculated the linear density to be 0.02kg/m, we can substitute these values into the formula:
v = sqrt(150N / 0.02kg/m) = sqrt(7500 m²/s²) = 86.6 m/s
So, the velocity of the wave in the string is 86.6 m/s.
Therefore, none of the provided options match the calculated results.
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