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Test time left: 54:27Select the correct answerWhat will be the output of the following Python code?def ct(): global y y+=3 print(y)y=8print("y")Options11yError11y

Question

Test time left: 54:27Select the correct answerWhat will be the output of the following Python code?def ct(): global y y+=3 print(y)y=8print("y")Options11yError11y

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Solution

The output of the given Python code will be an Error.

Here's the step by step explanation:

  1. The function ct() is defined, which includes a global variable y. The function increments y by 3 and then prints y.

  2. y is then defined as 8 outside the function.

  3. The string "y" is printed.

However, the function ct() is never called in the code. Therefore, the y inside the function and the y outside the function are treated as two different variables.

When Python tries to execute y+=3 inside the function, it throws an error because y is not previously defined inside the function. The global keyword only applies if the global variable is defined before the function is called.

So, the correct answer is Error.

This problem has been solved

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