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Factor completely, then place the factors in the proper location on the grid.10b2 +17b + 3

Question

Factor completely, then place the factors in the proper location on the grid.10b2 +17b + 3

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Solution

To factor the quadratic equation 10b^2 + 17b + 3 completely, we need to find two numbers that multiply to (10*3)=30 and add up to 17. These numbers are 15 and 2.

So, we rewrite the middle term of the quadratic equation as 15b + 2b:

10b^2 + 15b + 2b + 3

Next, we factor by grouping:

5b(2b + 3) + 1(2b + 3)

Now, we can see that (2b + 3) is a common factor:

(2b + 3)(5b + 1)

So, the factors of the quadratic equation 10b^2 + 17b + 3 are (2b + 3) and (5b + 1).

As for placing the factors in the proper location on the grid, it would depend on the specific grid or graph you are using. In general, you would plot the roots of the equation (the values of b that make the equation equal to zero) on the x-axis. The roots can be found by setting each factor equal to zero and solving for b:

2b + 3 = 0 --> b = -3/2

5b + 1 = 0 --> b = -1/5

So, the roots are b = -3/2 and b = -1/5. These are the points you would plot on the grid.

This problem has been solved

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