Sure, here is a Python solution for your problem:

```python
def max_profit(prices):
if len(prices)

Question

Sure, here is a Python solution for your problem:

```python
def max_profit(prices):
    if len(prices) < 2:
        return "Need at least two days of prices to make a trade"

min_price = prices[0]
    max_profit = prices[1] - prices[0]

for i in range(1, len(prices)):
        current_price = prices[i]
        potential_profit = current_price - min_price
        max_profit = max(max_profit, potential_profit)
        min_price = min(min_price, current_price)

return max_profit
```

Here's how it works:

1. If the list of prices has less than two elements, we return an error message because we need at least two prices to make a trade.

2. We initialize `min_price` to the first price and `max_profit` to the difference between the first two prices.

3. We iterate over the list of prices starting from the second price. For each price, we calculate the potential profit we could make if we bought at the minimum price we've seen so far and sold at the current price. We update `max_profit` if the potential profit is greater than the current `max_profit`.

4. We also update `min_price` if the current price is less than the `min_price` we've seen so far.

5. Finally, we return `max_profit`, which is the maximum profit we could have made.

This solution has a time complexity of O(n), where n is the number of prices, because we make one pass through the list of prices. It has a space complexity of O(1), because we only use a constant amount of space to store the minimum price and maximum profit.

Knowee AI · Accepted Answer