To solve the inequality -2(3z+2) -6z - 13, follow these steps:

Step 1: Distribute -2 to both terms inside the parentheses on the left side of the inequality:

-6z - 4 -6z - 13

Step 2: Add 6z to both sides of the inequality to cancel out the z term on both sides:

-4 -13

This is a true statement, which means the original inequality is true for all real numbers z. Therefore, the solution to the inequality is z ∈ R (all real numbers).

Question

To solve the inequality -2(3z+2) > -6z - 13, follow these steps:

Step 1: Distribute -2 to both terms inside the parentheses on the left side of the inequality:

-6z - 4 > -6z - 13

Step 2: Add 6z to both sides of the inequality to cancel out the z term on both sides:

-4 > -13

This is a true statement, which means the original inequality is true for all real numbers z. Therefore, the solution to the inequality is z ∈ R (all real numbers).

Knowee AI · Accepted Answer

To solve the inequality -2(3z+2) > -6z - 13, follow these steps:

Step 1: Distribute -2 to both terms inside the parentheses on the left side of the inequality:

-6z - 4 > -6z - 13

Step 2: Add 6z to both sides of the inequality to cancel out the z term on both sides:

-4 > -13

This is a true statement, which means the original inequality is true for all real numbers z. Therefore, the solution to the inequality is z ∈ R (all real numbers).

−2(3z+2)>−6z−13−2(3𝑧+2)>−6𝑧−13Solve the linear inequality for the given variable. Simplify and express your answer in algebraic notation.

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