What will this given code do?def POP(stack):   if len(stack)==0:      print(“Underflow”)   else:      stack.pop()OptionsWill delete all the elements from given stackWill delete last element from given stackWill delete first element from given stackWill produce error as no index is passed to pop()

The given code will delete the last element from the given stack.

Here's a step-by-step explanation:

1. The function POP(stack) is defined, which takes a list stack as an argument.
2. Inside the function, it first checks if the length of the stack is 0. If it is, it prints "Underflow". This is a condition to handle the case when the stack is empty, and there's nothing to pop.
3. If the stack is not empty (i.e., its length is not 0), it calls the pop() method on the stack. In Python, the pop() method removes and returns the last item in the list. Since no index is passed to pop(), it defaults to -1, which means the last item in the list.
4. So, the function will remove the last item from the stack.

Therefore, the correct option is "Will delete last element from given stack".