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Harshitha Mani walks from x = 8 m to x = -12 m in 8 seconds.  Then you can say that:Harshitha’s Velocity is -2.5 m/sHarshitha’s Average Speed is -2.5 m/sHarshitha’s Average Velocity is -2.5 m/sHarshitha’s Average Velocity is 2.5 m/s

Question

Harshitha Mani walks from x = 8 m to x = -12 m in 8 seconds.  Then you can say that:Harshitha’s Velocity is -2.5 m/sHarshitha’s Average Speed is -2.5 m/sHarshitha’s Average Velocity is -2.5 m/sHarshitha’s Average Velocity is 2.5 m/s

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Solution

The correct statement is: "Harshitha’s Average Velocity is -2.5 m/s".

Here's the step by step explanation:

  1. Velocity is a vector quantity, which means it has both magnitude (speed) and direction. In this case, Harshitha is moving from a positive position (x = 8 m) to a negative position (x = -12 m), which indicates a negative direction.

  2. To calculate the velocity, we subtract the final position from the initial position and divide by the time it took. So, (-12 m - 8 m) / 8 s = -20 m / 8 s = -2.5 m/s. The negative sign indicates the direction of the velocity, so Harshitha’s Average Velocity is -2.5 m/s.

  3. Speed, on the other hand, is a scalar quantity, which means it only has magnitude and no direction. Therefore, speed cannot be negative. So, the statement "Harshitha’s Average Speed is -2.5 m/s" is incorrect.

  4. The statement "Harshitha’s Velocity is -2.5 m/s" is also incorrect because it doesn't specify that this is an average velocity over the 8 seconds.

  5. The statement "Harshitha’s Average Velocity is 2.5 m/s" is incorrect because it doesn't take into account the negative direction of the movement.

This problem has been solved

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