Mai works as an IT technician for a local company. There are 100 computers on the company's network and 94 of them are not infected with a virus.Mai chooses a computer on the company's network at random. Let the event A and the event B be as follows.A: The computer Mai chooses is not infected with the virus.B: The computer Mai chooses is infected with the virus.Find the following probabilities. Write your answers as decimal numbers and do not round.=PA=PB
Question
Mai works as an IT technician for a local company. There are 100 computers on the company's network and 94 of them are not infected with a virus.Mai chooses a computer on the company's network at random. Let the event A and the event B be as follows.A: The computer Mai chooses is not infected with the virus.B: The computer Mai chooses is infected with the virus.Find the following probabilities. Write your answers as decimal numbers and do not round.=PA=PB
Solution
The event A is that the computer Mai chooses is not infected with the virus. There are 94 computers that are not infected. So, the probability of event A, P(A), is the number of favorable outcomes (the computer is not infected) divided by the total number of outcomes (the total number of computers).
P(A) = Number of favorable outcomes / Total number of outcomes P(A) = 94 / 100 P(A) = 0.94
The event B is that the computer Mai chooses is infected with the virus. There are 6 computers that are infected (100 total computers - 94 not infected = 6 infected). So, the probability of event B, P(B), is the number of favorable outcomes (the computer is infected) divided by the total number of outcomes (the total number of computers).
P(B) = Number of favorable outcomes / Total number of outcomes P(B) = 6 / 100 P(B) = 0.06
So, P(A) = 0.94 and P(B) = 0.06.
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