1,000−2𝑘=8001,000−2k=800 In 20102010, a forest was populated with 1,0001,000 deer. The population 𝑘k years after 20102010 was 800800. If the equation above represents this situation, which of the following is the best interpretation of the number 22 in this context?AThe deer population 𝑘k years after 20102010 BThe value of 𝑘k when the deer population was 800800 CThe difference between the deer population in 20102010 and the population 𝑘k years after 20102010 DThe average decrease in the deer population per year from 20102010 to 𝑘k years after 20102010
Question
1,000−2𝑘=8001,000−2k=800 In 20102010, a forest was populated with 1,0001,000 deer. The population 𝑘k years after 20102010 was 800800. If the equation above represents this situation, which of the following is the best interpretation of the number 22 in this context?AThe deer population 𝑘k years after 20102010 BThe value of 𝑘k when the deer population was 800800 CThe difference between the deer population in 20102010 and the population 𝑘k years after 20102010 DThe average decrease in the deer population per year from 20102010 to 𝑘k years after 20102010
Solution
Primero, resolvamos la ecuación para encontrar el valor de :
Restamos 800 de ambos lados de la ecuación:
Simplificamos:
Dividimos ambos lados entre 2:
Ahora, analicemos las opciones para interpretar el número en este contexto:
A. La población de ciervos años después de 2010.
- Esto no tiene sentido porque representa el número de años, no la población.
B. El valor de cuando la población de ciervos era 800.
- Esto no es correcto porque es 100, no 2.
C. La diferencia entre la población de ciervos en 2010 y la población años después de 2010.
- Esto no es correcto porque la diferencia es 200, no 2.
D. La disminución promedio en la población de ciervos por año desde 2010 hasta años después de 2010.
- Esto es correcto porque la población disminuye en 2 ciervos por año.
Por lo tanto, la mejor interpretación del número en este contexto es:
D. La disminución promedio en la población de ciervos por año desde 2010 hasta años después de 2010.
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