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dentify the probabilities for each number the wheel can stop at.Probability of stopping at number 0: P(0) = 0.75Probability of stopping at number 1: P(1) = 0.15Probability of stopping at number 2: P(2) = 0.102Calculate the probability of getting a sum of 0 after spinning the wheel twice. This is the probability of getting 0 on the first spin and 0 on the second spin.

Question

dentify the probabilities for each number the wheel can stop at.Probability of stopping at number 0: P(0) = 0.75Probability of stopping at number 1: P(1) = 0.15Probability of stopping at number 2: P(2) = 0.102Calculate the probability of getting a sum of 0 after spinning the wheel twice. This is the probability of getting 0 on the first spin and 0 on the second spin.

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Solution

The probability of getting a sum of 0 after spinning the wheel twice is the product of the probabilities of getting 0 on each spin.

Since the probability of stopping at number 0 on a single spin is P(0) = 0.75, the probability of getting 0 on two spins is the product of these probabilities.

So, P(0,0) = P(0) * P(0) = 0.75 * 0.75 = 0.5625

Therefore, the probability of getting a sum of 0 after spinning the wheel twice is 0.5625.

This problem has been solved

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