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Iron Oxide, Fe2O3, reacts with 25 mL of 30 M Hydrochloric acid, HCl. What is the mass of Iron(III) Chloride, FeCl3 formed? Round your answer to 4 s.f. The reaction equation and relative atomic masses have been provided:Fe2O3 + 6HCl --> 2FeCl3 + 3H2O Ar:Fe = 55.8Cl = 35.5O = 16.0H = 1.0Select your answer:Select your answerOPTION ALTERNATIVE 38.72 g 44.43 g 36.35 g 10.49 g 40.58 g

Question

Iron Oxide, Fe2O3, reacts with 25 mL of 30 M Hydrochloric acid, HCl. What is the mass of Iron(III) Chloride, FeCl3 formed? Round your answer to 4 s.f. The reaction equation and relative atomic masses have been provided:Fe2O3 + 6HCl --> 2FeCl3 + 3H2O Ar:Fe = 55.8Cl = 35.5O = 16.0H = 1.0Select your answer:Select your answerOPTION ALTERNATIVE 38.72 g 44.43 g 36.35 g 10.49 g 40.58 g

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Solution

To solve this problem, we need to follow these steps:

  1. Calculate the moles of HCl used. The molarity (M) is defined as moles of solute per liter of solution. So, moles = Molarity x Volume(L). Here, volume should be in liters. So, 25 mL = 0.025 L. Therefore, moles of HCl = 30 M x 0.025 L = 0.75 moles.

  2. From the balanced chemical equation, we know that 6 moles of HCl react with 1 mole of Fe2O3 to produce 2 moles of FeCl3. So, the moles of FeCl3 produced = (2/6) x moles of HCl = (2/6) x 0.75 = 0.25 moles.

  3. Now, calculate the molar mass of FeCl3. The molar mass is calculated by adding the atomic masses of all the atoms in a molecule. So, Molar mass of FeCl3 = (1 x 55.8) + (3 x 35.5) = 162.3 g/mol.

  4. Finally, calculate the mass of FeCl3 formed. Mass = moles x molar mass = 0.25 moles x 162.3 g/mol = 40.575 g.

So, the mass of FeCl3 formed is approximately 40.58 g when rounded to 4 significant figures. Therefore, the correct answer is 40.58 g.

This problem has been solved

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