What is the 15th term of an arithmetic progression whose first term is equal to its common difference and whose 3rd term is 9.a.45b.15c.60d.30
Question
What is the 15th term of an arithmetic progression whose first term is equal to its common difference and whose 3rd term is 9.a.45b.15c.60d.30
Solution
The first term (a) of the arithmetic progression is equal to the common difference (d). Given that the third term is 9, we can use the formula for the nth term of an arithmetic progression:
nth term = a + (n-1)d
Substituting the given values:
9 = a + (3-1)a 9 = 2a a = 9/2 = 4.5
So, the common difference d is also 4.5.
Now, to find the 15th term, we substitute these values into the formula:
15th term = a + (15-1)d 15th term = 4.5 + (14)*4.5 15th term = 4.5 + 63 15th term = 67.5
However, this answer is not in the options provided. Please check the question again.
Similar Questions
Find the 22nd term of the arithmetic progression whose first term is 20 and common difference is 1/3.a.27 2/3b.28c.27d.27 1/3
Find the 10th term of the arithmetic progression whose 4th term is 7 and whose 17th term is 72.a.47b.42c.32d.37
Thirteen times the thirteenth term of an arithmetic progressions equal to seven times the seventh term of the arithmetic progression. What is the twentieth term?a.- 1b.- 3c.0d.4
WHAT IS THE 5TH TERM IN THE GIVEN SEQUENCE1,3,6,9A. 10 B. 13 C. 14 D. 15
The sixth term and the eleventh term of a arithmetic progression are 30 and 55 respectively. Find the twenty-first term of the series.a.92 ½b.110c.105d.88 1/3
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.