If n is an even integer, then (i)n is equal to

For some integer n, the odd integer is represented in the form of:

For any integer m, every even integer is always of the form

An even number can be expressed as the square of an integer as well as a cube of another integer. Then the number has to be necessarily divisible by:

Prove that, if n is an odd number, then n2 + 1 is an even number.

Given an integer n, return true if it is a power of two. Otherwise, return false.An integer n is a power of two, if there exists an integer x such that n == 2x.