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Two moles of an ideal gas originally at 380 torr and 298 K are compressed at constant temperature to a final pressure of 680 torr. Use the ideal gas law to calculate the volumes of gas at the initial and final pressures.

Question

Two moles of an ideal gas originally at 380 torr and 298 K are compressed at constant temperature to a final pressure of 680 torr. Use the ideal gas law to calculate the volumes of gas at the initial and final pressures.

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Solution

Sure, let's use the ideal gas law to solve this problem. The ideal gas law is PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

Step 1: Convert the pressures from torr to atm because the gas constant R is usually defined with pressure in atm. 1 atm = 760 torr, so 380 torr = 380/760 = 0.5 atm and 680 torr = 680/760 = 0.895 atm.

Step 2: Use the ideal gas law to find the initial volume (V1). We know that n = 2 moles, R = 0.0821 L atm/(mol K), and T = 298 K. So, we can plug these values into the ideal gas law:

0.5 atm * V1 = 2 moles * 0.0821 L atm/(mol K) * 298 K

Solving for V1 gives V1 = (2 moles * 0.0821 L atm/(mol K) * 298 K) / 0.5 atm = 48.6 L.

Step 3: Use the ideal gas law again to find the final volume (V2) at the final pressure of 0.895 atm:

0.895 atm * V2 = 2 moles * 0.0821 L atm/(mol K) * 298 K

Solving for V2 gives V2 = (2 moles * 0.0821 L atm/(mol K) * 298 K) / 0.895 atm = 27.3 L.

So, the volume of the gas decreases from 48.6 L to 27.3 L when it is compressed at constant temperature from 380 torr to 680 torr.

This problem has been solved

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