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A 0.7 L latex balloon at 20°C is heated to 25°C with a hair dryer (bad idea!). Will the volume of the balloon increase or decrease?

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A 0.7 L latex balloon at 20°C is heated to 25°C with a hair dryer (bad idea!). Will the volume of the balloon increase or decrease?

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Solution 1

The volume of the balloon will increase. This is due to Charles's Law, which states that the volume of a gas is directly proportional to its temperature, provided the pressure and the amount of gas remain constant.

Here's a step-by-step explanation:

  1. Identify the initial volume (V1) and temperature (T1). In this case, V1 is 0.7 L and T1 is 20°C.

  2. Convert the temperatures from Celsius to Kelvin. The Kelvin scale is used in gas law problems. To convert, add 273.15 to the Celsius temperature. So, T1 is 20 + 273.15 = 293.15 K.

  3. Identify the final temperature (T2). In this case, T2 is 25°C, which is 25 + 273.15 = 298.15 K.

  4. Apply Charles's Law, which is V1/T1 = V2/T2. We know V1, T1, and T2, and we want to find V2 (the final volume).

  5. Solve for V2: V2 = V1 * T2 / T1 = 0.7 L * 298.15 K / 293.15 K = 0.71 L.

So, the volume of the balloon increases to 0.71 L when the temperature is increased to 25°C.

This problem has been solved

Solution 2

The volume of the balloon will increase. Here's why:

  1. The balloon is filled with air, and air is a gas. Gases have various properties that are related, these properties are pressure, temperature, and volume.

  2. According to Charles's Law, the volume of a gas is directly proportional to its temperature, provided the pressure and the amount of gas remain constant. This means that if the temperature increases, the volume also increases. If the temperature decreases, the volume decreases.

  3. In this case, the temperature of the balloon is increased from 20°C to 25°C. This is an increase in temperature.

  4. Therefore, according to Charles's Law, the volume of the balloon will also increase.

So, heating the balloon with a hair dryer (even though it's a bad idea) will cause the balloon to expand.

This problem has been solved

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