Which bond has the greatest ionic character?A.B – FB.C – FC.N – FD.F – F

The ionic character of a bond is determined by the difference in electronegativity between the two atoms involved in the bond. The greater the difference, the more ionic the bond is.

Here are the electronegativity values for the atoms involved:

• B (Boron) = 2.04
• C (Carbon) = 2.55
• N (Nitrogen) = 3.04
• F (Fluorine) = 3.98

Now, let's calculate the difference in electronegativity for each bond:

• B – F = |2.04 - 3.98| = 1.94
• C – F = |2.55 - 3.98| = 1.43
• N – F = |3.04 - 3.98| = 0.94
• F – F = |3.98 - 3.98| = 0

From these calculations, we can see that the B – F bond has the greatest difference in electronegativity, and therefore, it has the greatest ionic character.