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98. Find the missing term of the given series :1, 4, 27, 16, ?, 36, 343(A) 25 (B) 32 (C) 64 (D) 125

Question

  1. Find the missing term of the given series :1, 4, 27, 16, ?, 36, 343(A) 25 (B) 32 (C) 64 (D) 125
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Solution

The given series is a combination of two series: one is the cube of natural numbers (1^3, 2^3, 3^3, 4^3, 5^3, 6^3, 7^3) and the other is the square of natural numbers (1^2, 2^2, 3^2, 4^2, 5^2, 6^2).

The series is arranged in such a way that one term is from the cube series and the next term is from the square series.

So, the series looks like this:

1 (1^3), 4 (2^2), 27 (3^3), 16 (4^2), ?, 36 (6^2), 343 (7^3)

The missing term is the cube of 5 (5^3), which is 125.

So, the correct answer is (D) 125.

This problem has been solved

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