the magnitude of a charge on a particle which is moving with 10 metre per second is 2 coulomb now the velocity of the charge is doubled, then new charge is

The new velocity of second charged particle has a magnitude `x' times the initial velocity, where x is

When the distance between two charged particles is doubled, theforce between them becomes

A positively charged particle (charge q, mass m) is moving with constant velocity (of magnitude v0) in a region of space. In that region, a uniform electric field (of strength E) is applied for some time such that particle deviates by 60∘ and is moving twice as fast. The time for which the field acts is xmv0qE. Find the value of x2.

A particle having a charge of 1.6×10−19 1.6×10 −19   coulomb is moving with a speed of 7×107𝑚/𝑠 7×10 7 m/s   in a magnetic field of 4T perpendicular to it. Calculate the force experienced by the moving charged particle.2.24×10−12𝑁2.24×10 −12 N4.48×10−12𝑁4.48×10 −12 N4.48×10−11𝑁4.48×10 −11 N2.24×10−11𝑁2.24×10 −11 N

Two charged particles repel each other with a force F. If the charge of one of the particles is doubled and the distance between them is also doubled, then the force will beGroup of answer choicesF/2.F/4.2F.F.