limℎ→049+ℎ−7ℎ=h→0lim h49+h −7 =A.14B.7C.0D.−177−1 E.114141
Question
limℎ→049+ℎ−7ℎ=h→0lim h49+h −7 =A.14B.7C.0D.−177−1 E.114141
Solution
The given expression is a limit problem in calculus. Here's how to solve it:
Step 1: Rewrite the expression lim(h→0) [(49+h) - 7] / h
Step 2: Simplify the numerator = lim(h→0) [h + 42] / h
Step 3: Cancel out the common factor 'h' from the numerator and denominator = lim(h→0) 1 + 42/h
Step 4: As h approaches 0, 42/h approaches infinity. But the limit of a constant (1 in this case) is just the constant itself. So, the limit of the expression is 1.
Therefore, none of the given options (A.14, B.7, C.0, D.-177−1, E.114141) is correct. The correct answer should be 1.
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