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lim⁡ℎ→049+ℎ−7ℎ=h→0lim​ h49+h​ −7​ =A.14B.7C.0D.−177−1​ E.114141​

Question

lim⁡ℎ→049+ℎ−7ℎ=h→0lim​ h49+h​ −7​ =A.14B.7C.0D.−177−1​ E.114141​

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Solution

The given expression is a limit problem in calculus. Here's how to solve it:

Step 1: Rewrite the expression lim(h→0) [(49+h) - 7] / h

Step 2: Simplify the numerator = lim(h→0) [h + 42] / h

Step 3: Cancel out the common factor 'h' from the numerator and denominator = lim(h→0) 1 + 42/h

Step 4: As h approaches 0, 42/h approaches infinity. But the limit of a constant (1 in this case) is just the constant itself. So, the limit of the expression is 1.

Therefore, none of the given options (A.14, B.7, C.0, D.-177−1​, E.114141​) is correct. The correct answer should be 1.

This problem has been solved

Similar Questions

lim⁡ℎ→049+ℎ−7ℎ=h→0lim​ h49+h​ −7​ =

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1/2

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