If black kings, queens, and jacks are removed from a pack of 52 playing cards and a card is drawn at random from the remaining cards, then find the probability that the card drawn is a diamond.13/230.13043478260913/4613/52
Question
If black kings, queens, and jacks are removed from a pack of 52 playing cards and a card is drawn at random from the remaining cards, then find the probability that the card drawn is a diamond.13/230.13043478260913/4613/52
Solution
The question seems to be a bit jumbled, but I understand that you're asking for the probability of drawing a diamond from a deck of 52 cards, after removing all black kings, queens, and jacks. Here's how you can calculate it:
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First, let's determine the total number of cards left after removing the black kings, queens, and jacks. There are 4 kings, 4 queens, and 4 jacks in a deck, half of which are black. So, we remove 2 kings, 2 queens, and 2 jacks, which is a total of 6 cards. Subtracting these from the total number of cards in the deck (52), we get 46 cards.
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Next, let's determine the number of diamond cards in the deck. There are 4 suits in a deck (hearts, diamonds, clubs, and spades), each with 13 cards. So, there are 13 diamond cards.
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The probability of drawing a diamond is then the number of diamond cards divided by the total number of cards left in the deck. So, the probability is 13/46 = 0.2826 or 28.26% when rounded to two decimal places.
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