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How many such pairs of letters are there in the word MONITERED each of which has as many letters between them in the word (in both forward and backward directions) as they have between them in the english alphabetical series?OptionsNoneOneTwoMore than threeThree

Question

How many such pairs of letters are there in the word MONITERED each of which has as many letters between them in the word (in both forward and backward directions) as they have between them in the english alphabetical series?OptionsNoneOneTwoMore than threeThree

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Solution

To find the number of such pairs of letters in the word "MONITERED," we need to identify the letters that have the same number of letters between them in the word as they do in the English alphabetical series.

Step 1: Write down the English alphabetical series: A, B, C, D, E, F, G, H, I, J, K, L, M, N, O, P, Q, R, S, T, U, V, W, X, Y, Z.

Step 2: Identify the letters in the word "MONITERED": M, O, N, I, T, E, R, E, D.

Step 3: Count the number of letters between each pair of letters in the word "MONITERED" in both forward and backward directions.

  • Between M and O, there is one letter (N) in both the word and the alphabetical series.
  • Between O and N, there are no letters in both the word and the alphabetical series.
  • Between N and I, there are two letters (O and P) in both the word and the alphabetical series.
  • Between I and T, there are three letters (J, K, and L) in both the word and the alphabetical series.
  • Between T and E, there are four letters (U, V, W, and X) in both the word and the alphabetical series.
  • Between E and R, there are five letters (F, G, H, I, and J) in both the word and the alphabetical series.
  • Between R and E, there are five letters (Q, P, O, N, and M) in both the word and the alphabetical series.
  • Between E and D, there are four letters (F, G, H, and I) in both the word and the alphabetical series.

Step 4: Count the number of pairs that satisfy the condition. In this case, there are two pairs: M and O, and N and I.

Therefore, the answer is Two.

This problem has been solved

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