A stone is dropped from the edge of a roof(1) What is the time it takes for an object to fall a distance of 4.9 m?(0) What will be the velocity of the stone at the end of the fall?(iii) What will be the acceleration of the stone after 1 s and 5 s?
Question
A stone is dropped from the edge of a roof(1) What is the time it takes for an object to fall a distance of 4.9 m?(0) What will be the velocity of the stone at the end of the fall?(iii) What will be the acceleration of the stone after 1 s and 5 s?
Solution
(i) The time it takes for an object to fall a distance of 4.9 m can be calculated using the equation of motion: d = 0.5gt^2, where d is the distance, g is the acceleration due to gravity (9.8 m/s^2), and t is the time.
Rearranging the equation for t gives: t = sqrt((2d)/g) = sqrt((2*4.9)/9.8) = 1 second.
(ii) The velocity of the stone at the end of the fall can be calculated using the equation v = gt, where v is the velocity, g is the acceleration due to gravity (9.8 m/s^2), and t is the time.
Substituting the values gives: v = 9.8 * 1 = 9.8 m/s.
(iii) The acceleration of the stone after 1 s and 5 s will be the same because the acceleration due to gravity is constant for an object in free fall near the surface of the earth. So, the acceleration is 9.8 m/s^2 at both 1 s and 5 s.
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