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9. Let f be the function from R to R defined by f (x) = x2. Finda) f −1({1}) b) f −1({x | 0 < x < 1}) c) f −1({x | x > 4})

Question

  1. Let f be the function from R to R defined by f (x) = x2. Finda) f −1({1}) b) f −1({x | 0 < x < 1}) c) f −1({x | x > 4})
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Solution

Claro, vamos a resolver cada parte del problema paso a paso.

a) f1({1}) f^{-1}(\{1\})

Primero, recordemos que f(x)=x2 f(x) = x^2 . Queremos encontrar los valores de x x tales que f(x)=1 f(x) = 1 .

x2=1 x^2 = 1

Resolviendo esta ecuación, obtenemos:

x=±1 x = \pm 1

Por lo tanto,

f1({1})={1,1} f^{-1}(\{1\}) = \{-1, 1\}

b) f1({x0<x<1}) f^{-1}(\{x \mid 0 < x < 1\})

Queremos encontrar los valores de x x tales que 0<f(x)<1 0 < f(x) < 1 .

0<x2<1 0 < x^2 < 1

Esto implica que:

1<x<1 -1 < x < 1

Sin embargo, x0 x \neq 0 porque 02=0 0^2 = 0 no está en el intervalo 0<x<1 0 < x < 1 . Por lo tanto,

f1({x0<x<1})=(1,1){0} f^{-1}(\{x \mid 0 < x < 1\}) = (-1, 1) \setminus \{0\}

c) f1({xx>4}) f^{-1}(\{x \mid x > 4\})

Queremos encontrar los valores de x x tales que f(x)>4 f(x) > 4 .

x2>4 x^2 > 4

Esto implica que:

x>2ox<2 x > 2 \quad \text{o} \quad x < -2

Por lo tanto,

f1({xx>4})=(,2)(2,) f^{-1}(\{x \mid x > 4\}) = (-\infty, -2) \cup (2, \infty)

Espero que esto te

This problem has been solved

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