You are climbing a staircase. It takes n steps to reach the top.Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Example 1:Input: n = 2Output: 2Explanation: There are two ways to climb to the top.1. 1 step + 1 step2. 2 stepsExample 2:Input: n = 3Output: 3Explanation: There are three ways to climb to the top.1. 1 step + 1 step + 1 step2. 1 step + 2 steps3. 2 steps + 1 step Constraints:1 <= n <= 45
Question
You are climbing a staircase. It takes n steps to reach the top.Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top? Example 1:Input: n = 2Output: 2Explanation: There are two ways to climb to the top.1. 1 step + 1 step2. 2 stepsExample 2:Input: n = 3Output: 3Explanation: There are three ways to climb to the top.1. 1 step + 1 step + 1 step2. 1 step + 2 steps3. 2 steps + 1 step Constraints:1 <= n <= 45
Solution
This problem can be solved using dynamic programming. Here are the steps:
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Create an array dp of size n+1 to store the number of ways to reach each step. Initialize dp[0] and dp[1] as 1 because there is only one way to reach the first step (by taking one step) and one way to reach the second step (either by taking two steps at once or by taking one step twice).
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For each step from 2 to n, calculate the number of ways to reach that step by adding the number of ways to reach the previous step (dp[i-1]) and the number of ways to reach the step before the previous step (dp[i-2]). This is because you can reach the current step either by taking one step from the previous step or by
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