The thermal energy that causes the ice to melt is transferred from the chocolate drink as itcools. The loss of this thermal energy causes the temperature of the 275 g of chocolate drinkto fall by 15 0C. Calculate the specific heat capacity of the chocolate drink.specific heat capacity=
Question
The thermal energy that causes the ice to melt is transferred from the chocolate drink as itcools. The loss of this thermal energy causes the temperature of the 275 g of chocolate drinkto fall by 15 0C. Calculate the specific heat capacity of the chocolate drink.specific heat capacity=
Solution
To calculate the specific heat capacity of the chocolate drink, we can use the formula:
Q = mcΔT
where: Q is the heat energy transferred (in joules, J), m is the mass of the substance (in kilograms, kg), c is the specific heat capacity (in joules per kilogram per degree Celsius, J/kg°C), and ΔT is the change in temperature (in degrees Celsius, °C).
We are given: m = 275 g = 0.275 kg (since 1 kg = 1000 g), ΔT = 15°C, and Q is the thermal energy transferred from the chocolate drink to the ice, which causes the ice to melt.
However, we don't have the value of Q. If we knew the amount of ice that melted, we could calculate Q using the latent heat of fusion for ice (334,000 J/kg), but this information is not provided.
Therefore, we cannot calculate the specific heat capacity of the chocolate drink with the information given.
Similar Questions
Ice cubes of a total mass 80 g, and at 0 0C, are put into a chocolate drink of mass 275 g. All the icemelts as 25300 J of thermal energy transfers from the chocolate drink to the ice. The finaltemperature of the drink is 0 0C.(i) Calculate the specific latent heat of fusion for ice.
Ice cubes of a total mass 80 g, and at 0 0C, are put into a chocolate drink of mass 275 g. All the icemelts as 25300 J of thermal energy transfers from the chocolate drink to the ice. The finaltemperature of the drink is 0 0C.
(d) An ice cube has a temperature of −15.0 °CThe total thermal energy needed to raise the temperature of this ice cube to 0.0 °C andcompletely melt the ice cube is 5848 Jspecific heat capacity of ice = 2100 J/kg °Cspecific latent heat of fusion of ice = 334 000 J/kgCalculate the mass of the ice cube.________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________Mass of ice cube = _____________________________ kg(5)(Total 9 marks)Page 3 of 34
A chemist mixes 75.0 g of an unknown substance at 96.5°C with 1,150 g of water at 25.0°C. If the final temperature of the system is 37.1°C, what is the specific heat capacity of the substance? Use 4.184 J / g °C for the specific heat capacity of water. A. 368 J / g °C B. 13.1 J / g °C C. 0.368 J / g °C D. 0.0112 J / g °C
A 2.40 kg block of ice is heated with 5820 J of heat. The specific heat of ice is 2.10 J•g-1• °C-1. By how much will its temperature rise, assuming it does not melt? a 15,500,000 °C b 15,500 °C c 115 °C d 1.15 °C
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.