Calculate the n-factor of S2O3 for the following change.2S2O2−3→S4O2−6+2e−

The n-factor for a reaction is the total number of electrons gained or lost in the reaction. In this case, we are looking at the reaction:

2S2O3^2- → S4O6^2- + 2e^-

The n-factor is calculated by comparing the oxidation states of sulfur in the reactants and products.

In S2O3^2-, the average oxidation state of sulfur is +2. In S4O6^2-, the average oxidation state of sulfur is +2.5.

The change in oxidation state per sulfur atom is +2.5 - (+2) = +0.5.

Since there are 4 sulfur atoms changing their oxidation state, the total change is 4 * (+0.5) = +2.

Therefore, the n-factor of S2O3^2- in this reaction is 2.