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The manufacturer's guide states that the thermistor has a resistance of 12 kΩ at room temperature. The student wants to confirm the accuracy of this value before starting the investigation. At room temperature, the voltmeter shows a reading of 8 V. Determine if this reading is consistent with the manufacturer's value of resistance.

Question

The manufacturer's guide states that the thermistor has a resistance of 12 kΩ at room temperature. The student wants to confirm the accuracy of this value before starting the investigation. At room temperature, the voltmeter shows a reading of 8 V. Determine if this reading is consistent with the manufacturer's value of resistance.

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Solution

To determine if the voltmeter reading is consistent with the manufacturer's value of resistance, we can use Ohm's Law, which states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points, and inversely proportional to the resistance (R) between them. The formula is I = V/R.

However, in this case, we don't have the current. We only have the voltage (V) and the resistance (R). We can rearrange the formula to solve for the voltage: V = I*R.

Given that we don't have the current, we can't directly verify the manufacturer's value of resistance. We would need to know the current flowing through the thermistor to be able to do this.

If the student has an ammeter, they could measure the current and then use Ohm's Law to calculate the resistance. If the calculated resistance is close to 12 kΩ, then the manufacturer's value is accurate. If not, then it's not accurate.

This problem has been solved

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