The mass of a lift is 500 kg. When it ascends with an acceleration of 2 m/s2, the tension in the cable will be [g = 10 m/s2]A 6000 N B 5000 N C 4000 N D 50 N
Question
The mass of a lift is 500 kg. When it ascends with an acceleration of 2 m/s2, the tension in the cable will be [g = 10 m/s2]A 6000 N B 5000 N C 4000 N D 50 N
Solution
To solve this problem, we need to use the formula for force, which is F = m*a. In this case, the force is the tension in the cable, the mass (m) is 500 kg, and the acceleration (a) is the sum of the acceleration due to gravity and the acceleration of the lift, which is 10 m/s^2 + 2 m/s^2 = 12 m/s^2.
Step 1: Identify the given values. Mass (m) = 500 kg Acceleration due to gravity (g) = 10 m/s^2 Acceleration of the lift (a) = 2 m/s^2
Step 2: Add the acceleration due to gravity and the acceleration of the lift. Total acceleration = g + a = 10 m/s^2 + 2 m/s^2 = 12 m/s^2
Step 3: Substitute the given values into the formula for force. F = m*a = 500 kg * 12 m/s^2 = 6000 N
So, the tension in the cable when the lift ascends with an acceleration of 2 m/s^2 is 6000 N. Therefore, the answer is A) 6000 N.
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