The problem can be solved using the combination formula which is nCr = n! / r!(n-r)!.

First, we need to select 2 boys out of 10. The number of ways to do this is 10C2 = 10! / 2!(10-2)! = 45 ways.

Next, we need to select 2 girls out of 5. The number of ways to do this is 5C2 = 5! / 2!(5-2)! = 10 ways.

The total number of ways to select 2 boys and 2 girls is the product of the two, which is 45 * 10 = 450 ways.

So, the answer is A. 450.

Question

The problem can be solved using the combination formula which is nCr = n! / r!(n-r)!.

First, we need to select 2 boys out of 10. The number of ways to do this is 10C2 = 10! / 2!(10-2)! = 45 ways.

Next, we need to select 2 girls out of 5. The number of ways to do this is 5C2 = 5! / 2!(5-2)! = 10 ways.

The total number of ways to select 2 boys and 2 girls is the product of the two, which is 45 * 10 = 450 ways.

So, the answer is A. 450.

Knowee AI · Accepted Answer

The problem can be solved using the combination formula which is nCr = n! / r!(n-r)!.

First, we need to select 2 boys out of 10. The number of ways to do this is 10C2 = 10! / 2!(10-2)! = 45 ways.

Next, we need to select 2 girls out of 5. The number of ways to do this is 5C2 = 5! / 2!(5-2)! = 10 ways.

The total number of ways to select 2 boys and 2 girls is the product of the two, which is 45 * 10 = 450 ways.

So, the answer is A. 450.

n how many ways 2 boys and 2 girls can be selected from a class of 10 boys and 5 girls? Ops: A. 450 B. 900 C. 245 D. 512