[1 - cos(nπ/2) - sin(nπ/2)]^2, Z transform of the question

What is the z-transform of the signal x(n)=sin(jω0n)u(n)?a) z−1sinω01+2z−1cosω0+z−2b) z−1sinω01−2z−1cosω0−z−2c) z−1cosω01−2z−1cosω0+z−2d) z−1sinω01−2z−1cosω0+z−2

Z transform of it

y the integration by parts, we haveZ π−πf (x) cos(nx)dx

Find the Z-transform of 𝒏𝒄𝒐𝒔(𝒏 𝜽)

Find the Z-transform of 𝟐𝒏 + 𝟕 𝒔𝒊𝒏 (𝒏 𝝅𝟒 ) − 𝟔𝒂𝟐