rove that the set of vectors (1, 2), (3, 4) is linearly independent and spanning in R2
Question
rove that the set of vectors (1, 2), (3, 4) is linearly independent and spanning in R2
Solution
To prove that the set of vectors (1, 2), (3, 4) is linearly independent and spanning in R2, we need to follow these steps:
Step 1: Linear Independence We need to show that the only solution to the equation a*(1, 2) + b*(3, 4) = (0, 0) is a = 0 and b = 0.
This gives us the system of equations: 1a + 3b = 0 2a + 4b = 0
This system has only the trivial solution a = 0, b = 0. Therefore, the vectors are linearly independent.
Step 2: Spanning R2 To show that these vectors span R2, we need to show that any vector in R2 can be written as a linear combination of these vectors.
Let's take an arbitrary vector (x, y) in R2. We need to find scalars a and b such that: a*(1, 2) + b*(3, 4) = (x, y)
This gives us the system of equations: a + 3b = x 2a + 4b = y
This system has a solution for any (x, y), which means any vector in R2 can be written as a linear combination of (1, 2) and (3, 4). Therefore, these vectors span R2.
So, the set of vectors (1, 2), (3, 4) is linearly independent and spanning in R2.
Similar Questions
Define a span and a spanning set. Using the definition of a spanning set, demonstrate that(1, 1, 0), (4, 2, 1), (3, 1, 1) is not a spanning set of R3. In your answer you may use the definitions aspan and a spanning set, but not the concepts of a basis and dimension.
Suppose {v1,v2,U3, v4} is a linearly dependent spanning set for a vector space V. Show that each w in V can be expressed in more than one way)as a linear combination of v1,...,v4.
Are the vectors [−24],[7−2][−24],[7−2] and [3−6][3−6] linearly independent? Yes No
Find a basis for the subspace of R3 spanned by S.S = {(4, 4, 9), (1, 1, 2), (1, 1, 1)}STEP 1: Find the reduced row-echelon form of the matrix whose rows are the vectors in S. STEP 2: Determine a basis that spans S.
Determine whether the set S spans R3. If the set does not span R3, then give a geometric description of the subspace that it does span.S = {(1, 0, 3), (2, 0, −1), (4, 0, 5), (2, 0, 6)}
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.