Standard reduction potentials of the half reactions are given belowNi2+ + 2e– → Ni(s); E° = –0.25 VPb2+ + 2e– → Pb(s); E° = –0.13 VMg2+ + 2e– → Mg(s); E° = –2.36 VCa2+ + 2e– → Ca(s); E° = –2.87 VThe strongest oxidising and reducing agents are respectivelyMg2+ and NiPb2+ and CaCa2+ and PbNi2+ and Pb
Question
Standard reduction potentials of the half reactions are given belowNi2+ + 2e– → Ni(s); E° = –0.25 VPb2+ + 2e– → Pb(s); E° = –0.13 VMg2+ + 2e– → Mg(s); E° = –2.36 VCa2+ + 2e– → Ca(s); E° = –2.87 VThe strongest oxidising and reducing agents are respectivelyMg2+ and NiPb2+ and CaCa2+ and PbNi2+ and Pb
Solution
The strongest oxidizing agent is the one with the highest reduction potential, while the strongest reducing agent is the one with the lowest reduction potential.
From the given data, we can see that Pb2+ has the highest reduction potential (E° = –0.13 V), so it is the strongest oxidizing agent.
On the other hand, Ca2+ has the lowest reduction potential (E° = –2.87 V), so it is the strongest reducing agent.
Therefore, the strongest oxidizing and reducing agents are Pb2+ and Ca2+ respectively.
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