What is the value of b in the solution of the system of equations below? 6a + 3b = 12-2a + b = -8
Question
What is the value of b in the solution of the system of equations below? 6a + 3b = 12-2a + b = -8
Solution
To find the value of b in the system of equations, we can use the method of substitution or elimination. Here, we will use the elimination method.
The system of equations is:
6a + 3b = 12 -2a + b = -8
First, we can multiply the second equation by 3 to make the coefficients of b in both equations the same:
-6a + 3b = -24
Now we have:
6a + 3b = 12 -6a + 3b = -24
We can add these two equations together:
(6a - 6a) + (3b + 3b) = 12 - 24 0a + 6b = -12
Simplify to get:
b = -12 / 6 b = -2
So, the value of b in the solution of the system of equations is -2.
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